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Math Help - factoring

  1. #1
    Senior Member euclid2's Avatar
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    factoring

    How do i factor 15AsquaredBcubed+10AsquaredBsquared-5ABcubed?
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  2. #2
    Super Member Matt Westwood's Avatar
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    15A^2B^3+10A^2B^2+5AB^3

    In each bit you can divide by 5 without leaving any remainder.

    You can also see there's an A in each bit.

    Also, there's a B in each bit. In fact, there's at least 2 B's in each bit.

    So you can extract a 5, an A and two B's.

    This gives, for each bit:

    5AB^2 \times 3AB

    5AB^2 \times 2A

    5AB^2 \times B

    So putting it all together we get:

    5AB^2 (3AB + 2A + B).
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  3. #3
    Junior Member
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    Hi,

    =15A^2B^3+10A^2B^2-5AB^3
    t taking common of 5AB^2

    =5AB^2(3AB+2A-B) is the answer
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