How do i factor 15AsquaredBcubed+10AsquaredBsquared-5ABcubed?
In each bit you can divide by 5 without leaving any remainder.
You can also see there's an in each bit.
Also, there's a in each bit. In fact, there's at least 2 's in each bit.
So you can extract a 5, an and two 's.
This gives, for each bit:
So putting it all together we get:
.