a, b, c, d, e are real numbers such that

a + b + c + d + e = 8

a^2 + b^2 + c^2 + d^2 + e^2 = 16.

What is the largest possible value of e?

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- Jul 18th 2008, 10:52 AMperashreal numbers
a, b, c, d, e are real numbers such that

a + b + c + d + e = 8

a^2 + b^2 + c^2 + d^2 + e^2 = 16.

What is the largest possible value of e? - Jul 19th 2008, 12:18 AMJaneBennet
Let’s suppose $\displaystyle a$, $\displaystyle b$, $\displaystyle c$, $\displaystyle d$ are non-negative. (Obviously $\displaystyle e$ will have to be positive if we want to maximize it.)

Applying AM–GM to the first equation gives

$\displaystyle 8-e=4\left(\frac{a+b+c+e}{4}\right)\ge\sqrt[4]{abcd}$

$\displaystyle \therefore\ e\le8-4\sqrt[4]{abcd}$

and*e*is maxed when $\displaystyle a=b=c=d$.

This is consistent with the application of AM–GM to the second equation, when we get

$\displaystyle e^2\le16-4\sqrt[4]{a^2b^2c^2d^2}=16-4d^2$ when $\displaystyle a^2=b^2=c^2=d^2$.

(Clearly, for positive*e*,*e*is maxed if and only $\displaystyle e^2$ is maxed.)

Solving those two equations in $\displaystyle e$ and $\displaystyle d$ gives $\displaystyle e=\frac{16}{5}$ as the maximum value for $\displaystyle a,b,c,d\ge0$.

If some or all of $\displaystyle a$, $\displaystyle b$, $\displaystyle c$, $\displaystyle d$ are negative, some other method may have to be tried.