x^2-9/6x^2-x-2 divded by x^2+x-6/3x^2-8x+4
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Originally Posted by cruxkitty x^2-9/6x^2-x-2 divded by x^2+x-6/3x^2-8x+4 $\displaystyle \frac{x^2-9}{6x^2-x-2}\div\frac{x^2+x-6}{3x^2-8x+4}=\frac{x^2-9}{6x^2-x-2}\times\frac{3x^2-8x+4}{x^2+x-6}$ $\displaystyle \frac{(x-3)(x+3)}{(3x-2)(2x+1)}\times\frac{(3x-2)(x-2)}{(x+3)(x-2)}=\frac{x-3}{2x+1}$
Last edited by masters; Jul 18th 2008 at 08:04 AM. Reason: Found an error!
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