Determine the equation of a line with an x-intercept of 4 and passing through the point(5,2)

Am I doing it correctly?

y = m(x - p) + q

y=4(x-5)+2

y=4x-20+2

y=4x-18

Thanks

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- Jul 10th 2008, 10:48 AMeuclid2equation of a line
Determine the equation of a line with an x-intercept of 4 and passing through the point(5,2)

Am I doing it correctly?

**y = m(x - p) + q**

y=4(x-5)+2

y=4x-20+2

y=4x-18

Thanks

- Jul 10th 2008, 11:11 AMSimplicity
**Explanation:**

You know 2 points which are [as you are told it passes x-axis through which occurs when ] and .

An equation of a straight line is in the form: where and are your variables, is your gradient and is your y-intercept.

Gradient is calculated by where and are two co-ordinates.

Use this gradient value and any co-ordinates to find the general form of the equation using where are any co-ordinates of the line.

**The method and working out:**

The two co-ordinates are and .

Check this with the other co-ordinates, .

Therefore the equation of the line is .