• Jul 5th 2008, 09:01 PM
Hypertension
I need a little help simplifying this problem.

http://img71.imageshack.us/img71/8021/lesson3195dg3.gif

=___ 1 ____ + x-1
(2x-1)(2x-1) (2x-1)

I can get this far, but then I get stuck.
I need to find the least common denomitor next and I think it's $\displaystyle (2x-1)(2x-1)$ but I'm not sure.

somehow this problem is supposed to equal
http://img71.imageshack.us/img71/201...n3s20q4ih7.gif

?
• Jul 5th 2008, 09:13 PM
Reckoner
Quote:

Originally Posted by Hypertension
I need a little help simplifying this problem.

http://img71.imageshack.us/img71/8021/lesson3195dg3.gif

=___ 1 ____ + x-1
(2x-1)(2x-1) (2x-1)

I can get this far, but then I get stuck.
I need to find the least common denomitor next and I think it's $\displaystyle (2x-1)(2x-1)$ but I'm not sure.

That is correct:

$\displaystyle \frac1{(2x - 1)^2} + \frac{x-1}{2x-1}$

$\displaystyle =\frac1{(2x - 1)^2} + \frac{(x-1)(2x - 1)}{(2x-1)(2x-1)}$

$\displaystyle =\frac{1 + (x-1)(2x - 1)}{(2x-1)^2}$

You can take it from here, yes?
• Jul 5th 2008, 09:25 PM
Hypertension
Yep.

After multiplying I came up with:

$\displaystyle \frac{1+2x^2-3x+1}{(2x-1)^2}$

$\displaystyle \frac{2x^2-3x+2}{(2x-1)^2}$