Can you please elaborate more on your question? Be specific.
(a) can be any length
(b) can be any width
(c) can be any angle
My starting point for this formula is (c) = 90 degrees
if (c) was less than 90 or greater and i know than angle and know the sizes for (a) and (b)
What formula can i use to find the distance between a&d
hope u can help.
A B Lenght 1500mm
D C length 1500mm
B C width 500mm
(Angle) A (B) C = 92 degrees (or any given angle)
(Angle) D (C) B = 92 degrees ( or any given angle)
Formula to work out distance between A & D
hope this helps more
I've tried to draw what I think you have described. Turns out to be an isosceles trapezoid with base angles of 92 degrees and 88 degrees, respectively (total interior angle = 360 degrees in a quadralateral).
XY=500 since BY is parallel to CY, making BC = XY.
AX = DY since triangles ABX and DCY are congruent.
To find AX, use