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Math Help - can you help with a formula

  1. #1
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    can u help with a formula

    (a) can be any length
    (b) can be any width
    (c) can be any angle

    My starting point for this formula is (c) = 90 degrees


    a d
    . .
    |
    |
    |
    |
    c---------b

    if (c) was less than 90 or greater and i know than angle and know the sizes for (a) and (b)

    What formula can i use to find the distance between a&d

    hope u can help.

    chees jimE
    Last edited by jime831; July 5th 2008 at 09:14 AM.
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  2. #2
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    Can you please elaborate more on your question? Be specific.
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  3. #3
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    hi

    just looked at my post (c) was in the wrong place please look again. What more do u need me t tell u about this question. i am very poor at maths and maybe i have not explained things right

    cheers jim
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  4. #4
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    can you help with a formula

    A D
    . .
    . .
    . .
    ......................
    b C

    A B Lenght 1500mm
    D C length 1500mm

    B C width 500mm

    (Angle) A (B) C = 92 degrees (or any given angle)

    (Angle) D (C) B = 92 degrees ( or any given angle)

    Formula to work out distance between A & D

    hope this helps more

    jimE
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  5. #5
    Super Member flyingsquirrel's Avatar
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    Hello

    You should use the tags [code] text of the "drawing" [/code] to "draw" otherwise the forum deletes the spaces when they are too numerous. (i.e. when there are more than two consecutive spaces)

    Code:
    A                    D
    .                    .
    .                    .
    .                    .
    ......................
    b                    C
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  6. #6
    A riddle wrapped in an enigma
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    Quote Originally Posted by jime831 View Post
    A D
    . .
    . .
    . .
    ......................
    b C

    A B Lenght 1500mm
    D C length 1500mm

    B C width 500mm

    (Angle) A (B) C = 92 degrees (or any given angle)

    (Angle) D (C) B = 92 degrees ( or any given angle)

    Formula to work out distance between A & D

    hope this helps more

    jimE

    I've tried to draw what I think you have described. Turns out to be an isosceles trapezoid with base angles of 92 degrees and 88 degrees, respectively (total interior angle = 360 degrees in a quadralateral).

    XY=500 since BY is parallel to CY, making BC = XY.

    AX = DY since triangles ABX and DCY are congruent.

    To find AX, use

    \cos 88 = \frac{AX}{1500}\Longrightarrow AX=1500 \cos88

    AD=AX + XY + DY

    Substituting,

    AD=1500\cos88 + 500 + 1500\cos88\Longrightarrow500+3000\cos88\approx552.  3592
    Attached Thumbnails Attached Thumbnails can you help with a formula-trapezoid.bmp  
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