Results 1 to 3 of 3

Math Help - please help

  1. #1
    Newbie
    Joined
    Mar 2008
    Posts
    9

    please help

    check if im right!
    (2x^3y^-2)^-2 = y^4/4x^6
    -5x^2y^4z^6/45x^7y^-8z^4 = -y^12z^2/9x^5
    6.2 * 10^4/3.1*10^-2 =2.6*10^6 = 2000000
    (3.25*10^-6)*(2.4*10^2) = 7.8*10^4

    M= cubed root 1-p, when p=28
    is M = to -3?

    Thanks in advance!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor Reckoner's Avatar
    Joined
    May 2008
    From
    Baltimore, MD (USA)
    Posts
    1,024
    Thanks
    75
    Awards
    1

    Smile

    Quote Originally Posted by missunique View Post
    check if im right!
    (2x^3y^-2)^-2 = y^4/4x^6 [Yes!]
    -5x^2y^4z^6/45x^7y^-8z^4 = -y^12z^2/9x^5 [Yes!]
    6.2 * 10^4/3.1*10^-2 =2.6*10^6 = 2000000 [Yes!]
    (3.25*10^-6)*(2.4*10^2) = 7.8*10^4 [Yes!]

    M= cubed root 1-p, when p=28
    is M = to -3? [Yes!]

    Thanks in advance!
    One thing though: your notation is a little ambiguous. When writing expressions in this way, it is conventional to perform multiplication and division from left to right, so that your denominators should really be placed in parentheses if these are to be correct (this problem does not arise when using the normal \frac ab notation, however).
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Mar 2008
    Posts
    9

    Smile

    thanks for that. i really appreciate it.
    Follow Math Help Forum on Facebook and Google+


/mathhelpforum @mathhelpforum