where is the second page of assignment three?
i just finish the home work........can any one check my work correct me if i didnt get it right, i only done the questions that i can solve.....and can any one do question #4,9,10,12 (b,c) ,13,14,15,16 <- those are the one i dont know how to solve .........
Question 4.
(a) If for two events and
,
then as:
we have:
.
(b) A dice is rolled twice. The first roll is a 2, what is the probability
that the sum of the two rolls is greater than 6?
that is the probability of the sum being greater than 6 given the first roll
is a 2, is the sum of the probabilities that the second roll is a 5 and that
the second roll is 6. So:
RonL
Virus.BagelJQ.Dllhow did u get the 1.75?
Since you are looking for a 92% CI the upper limit must cut off 4% ofOriginally Posted by sonymd23
the area under the normal density above the limit (the lower limit will cut off
the other 4% below, to leave the 92% you require). So the area under the
normal density curve below the upper limit is 96% which is what you look up
in a standard normal table to get 1.75.
RonL
When you use a continuous normal distribution to approximate a binomial probability, you need to move 0.5 units to the left and right of the midpoint. This is so you can include all possible x-values in the interval.
This is called a continuity correction
For instance, let's convert the following binomial to normal distribution.
The probability of getting between 200 and 250 successes, inclusive.
The discrete midpoint values are 200, 201, 202,....., 250. The interval for the
normal distribution is 199.5<x<250.5