Hey guys!

I just wanted to say that I really appreciate this forum. I'm doing some power studying for a college algebra test (I'm in high school) so I appreciate the help with the "power studying" I'm doing.

Take a look at this sigma-related problem...

A ball is dropped from a height ofhfeet and repeatedly bounces off the floor. After each bounce, the ball reaches a height that is $\displaystyle \frac2 3$ of the height from which is previously fell. For example, after the first bounce, the ball reaches a height of $\displaystyle \frac2 3$hfeet. Which of the following represents the total number of feet the ball travels between the first and the sixth bounce?Answer:$\displaystyle \sum_{i=1}^5$ (2h)$\displaystyle (\frac2 3)^i$

I understand how sigma works and stuff, but why2h$\displaystyle (\frac2 3)^i$? Why the "2" in 2h? I don't see anywhere in the actual problem where is calls to double something? Thanks... I'm sure it's something simple I'm forgetting...