A long uniform beam is pivoted at one end. A force of 300N is applied to hold the beam horizontally.
What is the weight of the beam?
Need Help... Don't know how to start
I can't really help you exactly.. though doesn't it have something to see with the strenght of gravity? You need an amount of strenght equal to the gravity to hold the beam in air.
This is just a gamble... so you best wait 'till someone proves me wrong (which 'll probably be the case but anyway...)
The strenght of a gravity field:
As they apply 300N to hold the beam in the air...
I could be terribly wrong though...
Edit: and 'topsquark' has proven me wrong so ignore me ^^
The weight W of the beam creates a right-turning momentum
while the force F = 300 N creates a left-turning momentum of
Both momenti must be equal that means the beam doesn't turn in any direction: