Me again
How do I convert the following units
To convert units, treat the units as variables, and use a "conversion factor" to cancel out the old units. For example:
$\displaystyle 18\text{ in} = 18\text{ in}\left(\frac11\right) = 18\text{ in}\left(\frac{1\text{ ft}}{12\text{ in}}\right)$
$\displaystyle = \frac{18\text{ in}\cdot\text{ft}}{12\text{ in}} = \frac{18}{12}\cdot\frac{\text{in}\cdot\text{ft}}{\ text{in}} = \frac32\cdot\frac{\not\text{in}\cdot\text{ft}}{\no t\text{in}} = \frac32\text{ ft}$
Similarly, for number 2:
$\displaystyle 1\frac{\text{BTU}\cdot\text{in}}{^\circ\text{F}\cd ot\text{ft}^2\cdot\text{hr}}$
$\displaystyle = 1\frac{\text{BTU}\cdot\text{in}}{^\circ\text{F}\cd ot\text{ft}^2\cdot\text{hr}}
\left(\frac{1054.8\text{ J}}{1\text{ BTU}}\right)
\left(\frac{1\text{ W}\cdot\text{s}}{1\text{ J}}\right)
\left(\frac{1\text{ ft}}{12\text{ in}}\right)^2
\left(\frac{1\text{ in}}{0.0254\text{ m}}\right)
\left(\frac{9^\circ\text{F}}{5\text{ K}}\right)
\left(\frac{1\text{ hr}}{3600\text{ s}}\right)
$
And, as long as I didn't make a mistake in typing all of that, all of your units should cancel and you will be left with units of $\displaystyle \text{W}\text{m}^{-1}\text{K}^{-1}$. The other questions are fairly similar.
It was an example that I made up on the spot (convert 18 inches to feet) just to illustrate the basic process.
That work is actually for part (i) (when I said it was for the second part that was a typo; I apologize). The working for the second part is quite similar.