I was just wondering because I can't quite remember
The total surface area would be the area of the Triangular bases plus the area of the sides
The area of a Triangle is $\displaystyle A_t=\frac{1}{2}bh$
The area of the side would be the perimeter $\displaystyle P_t$ of the triangle multiplied by the height $\displaystyle h_p$ of the prism.
So the surface area would be
$\displaystyle S=2A_t+P_t\cdot h_p$