Maria is 6 times as old as Tina. In 20 years, Maria will be only twice as old as Tina. How old is Maria now?
I find the easiest way to do a problem is to write everything mathematically.Originally Posted by Judi
first, define your variables...
Next, write out what you know.
Right now Maria is 6 times as old as Tina, therefore...
In 20 years Maria will only be twice as old as Tina, therefore...
Now we solve both equations for
Now we combine the two equations...
multiply by 6
extend...
multiply by 3
subtract from both sides...
Voila!
Hello, Judi!
Here's another approach . . . with one variable.
Maria is 6 times as old as Tina.
In 20 years, Maria will be only twice as old as Tina.
How old is Maria now?
Let = Tina's age.
Since Maria's age is 6 times Tina's age,
. . then = Maria's age.
In 20 years, they will both be 20 years older.
. . Tina will be years old.
. . Maria will be years old.
In the future, Maria's age is twice Tina's age.
. . . . . . . . . . . . . .
. . . . . . . . . . . .
And there is your equation . . . go for it!