# Linear equation to Inequality problem

• May 28th 2008, 12:38 PM
Bica
Linear equation to Inequality problem
I've done all these sections already and am stuck on Part 4. The other parts are necessary though so you can figure out Part 4.

Part 1
Band A charges $600 to play for the evening. Band B charges$350 plus $1.25 for each ticket sold. Write a linear equation for the cost of each band. Graph each equation and find the number of tickets for which the cost of the two bands will be equal. Band A- C=0x + 600 Band B- C=1.25x + 350 At 200 tickets they would be equal Part 2 A caterer charges a fixed cost for preparing dinner plus a cost for each person served. You know that the cost for 100 people will be$750 and the cost for 150 people will be $1050. Find the caterer's fixed cost and the cost per person served. 1(750= 100x + y) ààààà 750= 100x + 1y -1(1050= 150x + y) -1050= -150x + -1y -300 = -50x /-50 /-50 750=100(6) + y ßßßßß 6 = x 750= 600 + y y= 150 Fixed cost =$150
Cost per student = $6 Part 3 Use your information from the first two sections of this project. Assume that 200 people will come to the dance. Write a report listing which band you would choose and the cost per ticket that you need to charge to cover expenses. Then repeat the process assuming that 300 people will come. 200 students 0(200) + 600 = 600 à Band A 1.25(200) + 350 = 600 à Band B Catering: C= 200(6) + 150 C= 1350 1350 + 600 = 1950 1950/200 =$9.75 per ticket

300 students
0(300) + 600 = 600 à Band A
1.25(300) + 350 = 725 à Band B
Catering:
C= 300(6) + 150
C= 1950
1950 + 600 = 2250
2250/300 = $8.50 per ticket Part 4 In part 3 you found two ticket prices. Each price covers the cost of the dance under certain conditions. Decide what the ticket price should be. Plan for between 200 and 300 people. -If your objective is to keep the ticket price as low as possible, even at the risk of not covering your costs, which ticket price would you select? Based on this choice, write a linear equation that gives the total amount collected for ticket sales. Change your equation to an inequality to indicate that this represents the least amount of money you expect to collect from ticket sales. Would it be C = 250(6.00) C ≤ 250 (6.00) Since you could pick any number between 200 and 300? -If your objective is to be sure that you are able to cover the cost of the dinner dance, which ticket price would you select? Based on this choice, write a linear equation that gives the total amount collected for ticket sales. Change your equation to an inequality to indicate that this represents the least amount of money you expect to collect from ticket sales. __________________________________________________ __ -The two inequalities you have written, along with x>200 and x<300, form a system of linear inequalities. Graph this system to show the total amount recieved from ticket sales __________________________________________________ __________ Thank you, • May 28th 2008, 06:43 PM Reckoner Hi, Bica! Quote: Originally Posted by Bica Part 3 ... 1950 + 600 = 2250 2250/300 =$8.50 per ticket

This should be $\displaystyle 1950 + 600 = 2550$, but I suppose that was a typo since 2550/300 is still 8.5.
Quote:

Originally Posted by Bica
Part 4

In part 3 you found two ticket prices. Each price covers the cost of the dance under certain conditions. Decide what the ticket price should be. Plan for between 200 and 300 people.
-If your objective is to keep the ticket price as low as possible, even at the risk of not covering your costs, which ticket price would you select? Based on this choice, write a linear equation that gives the total amount collected for ticket sales. Change your equation to an inequality to indicate that this represents the least amount of money you expect to collect from ticket sales.

Would it be
C = 250(6.00)
C ≤ 250 (6.00)
Since you could pick any number between 200 and 300?

Well, if you want to make the price as low as possible, assume that the minimum number of people will show up (200) and base your price off of that. So, if $\displaystyle C$ is the amount of money we collect, then at minimum we would get $\displaystyle 200\cdot6.00 = 1200$, and we have

$\displaystyle C\geq\$1200$Quote: Originally Posted by Bica -If your objective is to be sure that you are able to cover the cost of the dinner dance, which ticket price would you select? Based on this choice, write a linear equation that gives the total amount collected for ticket sales. Change your equation to an inequality to indicate that this represents the least amount of money you expect to collect from ticket sales. This time, we want to plan for the maximum number of people (300) so that we can be sure to cover our cost no matter what. I assume that that last sentence should read "this represents the greatest amount of money you expect to collect," and so we have$\displaystyle C\leq\$300\cdot8.5=\$2550$and$\displaystyle \$1200\leq C\leq\$2550\$

Can you graph this?