Originally Posted by

**sean.1986** If the number if days in a year was a multiple of 7, then a given day would land on the same weekday every year because the week and year cycles would be aligned. If the year was 7 days long, what would the 8th day be? If they were 14 days long, what would the 15th day land on? The same as the first day, right?

However,

365/7 = 52 and 1/7th (i.e. one day longer than 52 weeks)

366/7 = 52 and 2/7ths (i.e. two days longer than 52 weeks)

So if, say, in a normal 365 day year, the first day was Tuesday...

The first 52 weeks would be

[Tue,Wed,Thu,Fri,Sat,Sun,Mon]

Then the spare day at the end of the year would be a Tuesday.

Making the first day of the next year a Wednesday

If it were a leap year, then you would have 2 spare days after the 52 - Tuesday and Wednesday, making the first day of the next year a Thursday.