# day of month

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• May 23rd 2008, 11:34 PM
neha1
day of month
first day of 1999 is sunday.what day is the last day?
• May 24th 2008, 12:02 AM
Aryth
This is pretty simple, there's 365 days in a year. Divide 364 (We already know Sunday) by 7, take the remainder and count from Sunday and you'll have your answer:

$\frac{364}{7} = 52 \ remainder \ 0$

The end of the year is also a Sunday. If it is a leap year, it will be the day after that.
• May 24th 2008, 10:03 AM
Isomorphism
Quote:

Originally Posted by hena
first day of 1999 is sunday.what is the last day

I will give you 2 hints:

(Hint 1)
1999 wasnt a leap year. So it had 365 days. Sunday repeats for every 7 days.... that is if 1st is a sunday, so is 8th Jan, 15th Jan and so on.....

(Hint 2)
365 = 1 + 7 x 52
• May 26th 2008, 05:32 PM
neha1
any other suggestion
is tat mean the answer is sunday
but they have not given sunday as an option for me
the option they given are
monday,wednesday
friday,saturday
• May 26th 2008, 05:41 PM
Jen
:D

I was wrong.

Sorry
• May 26th 2008, 06:09 PM
Aryth
It's not monday... If you look at any calendar that has many years recorded on it... All years start and end on the same day of the week, unless it is a leap year, then it ends on the day after.

You cannot include a day once it has been considered already. If you see it started on Sunday and count a week after that, you get Sunday:

Sunday...

Monday... 1
Tuesday.. 2
Wednesday... 3
Thursday. 4
Friday..... 5
Saturday. 6
Sunday... 7

If you continue this till the end of the year, you get 364 days.

That means, all years start and end on the same day except on Leap Year.
• May 26th 2008, 06:25 PM
Jen
Quote:

Originally Posted by Aryth
It's not monday... If you look at any calendar that has many years recorded on it... All years start and end on the same day of the week, unless it is a leap year, then it ends on the day after.

You cannot include a day once it has been considered already. If you see it started on Sunday and count a week after that, you get Sunday:

Sunday...

Monday... 1
Tuesday.. 2
Wednesday... 3
Thursday. 4
Friday..... 5
Saturday. 6
Sunday... 7

If you continue this till the end of the year, you get 364 days.

That means, all years start and end on the same day except on Leap Year.

Oh, you are correct, thank you. The first day of the next year would be a monday. Not the last day of the same year.

:p
• May 26th 2008, 11:22 PM
neha1
so which is rite
give me a suggestion plz
can i send the ans as monday???
• May 27th 2008, 06:12 AM
Jen
Quote:

Originally Posted by neha1
give me a suggestion plz
can i send the ans as monday???

I believe that the first day of the next year would be a Monday, however Aryth was correct every year other than leap years end on the same day.
So if you question asks what day the next year began on then yes, it would be Monday.
• May 27th 2008, 06:42 AM
sean.1986
If the number if days in a year was a multiple of 7, then a given day would land on the same weekday every year because the week and year cycles would be aligned. If the year was 7 days long, what would the 8th day be? If they were 14 days long, what would the 15th day land on? The same as the first day, right?

However,

365/7 = 52 and 1/7th (i.e. one day longer than 52 weeks)

366/7 = 52 and 2/7ths (i.e. two days longer than 52 weeks)

So if, say, in a normal 365 day year, the first day was Tuesday...

The first 52 weeks would be

[Tue,Wed,Thu,Fri,Sat,Sun,Mon]

Then the spare day at the end of the year would be a Tuesday.

Making the first day of the next year a Wednesday

If it were a leap year, then you would have 2 spare days after the 52 - Tuesday and Wednesday, making the first day of the next year a Thursday.
• May 27th 2008, 06:54 AM
masters
And of course, we know that the actual 1st day of 1999 was on a Friday.
• May 27th 2008, 09:21 AM
neha1
Quote:

Originally Posted by sean.1986
If the number if days in a year was a multiple of 7, then a given day would land on the same weekday every year because the week and year cycles would be aligned. If the year was 7 days long, what would the 8th day be? If they were 14 days long, what would the 15th day land on? The same as the first day, right?

However,

365/7 = 52 and 1/7th (i.e. one day longer than 52 weeks)

366/7 = 52 and 2/7ths (i.e. two days longer than 52 weeks)

So if, say, in a normal 365 day year, the first day was Tuesday...

The first 52 weeks would be

[Tue,Wed,Thu,Fri,Sat,Sun,Mon]

Then the spare day at the end of the year would be a Tuesday.

Making the first day of the next year a Wednesday

If it were a leap year, then you would have 2 spare days after the 52 - Tuesday and Wednesday, making the first day of the next year a Thursday.

can u plz make it more clear,its very urgent....
which option(mon,wed,fri,sat) should i choose among this..plz help me out
• May 27th 2008, 09:28 AM
sean.1986
Basically, the last and first day of 1999 were the same day.
• May 27th 2008, 09:54 AM
neha1
plz............
Quote:

Originally Posted by sean.1986
Basically, the last and first day of 1999 were the same day.

but i told they have not given sunday as an option
• May 27th 2008, 09:56 AM
sean.1986
There's something wrong with the question, then, because all leap years land on years that are multiples of 4.
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