if a man walks at the rate of 5kmph,he misses a train by only 7 min.however if he walks at the rate of 6kmph he reaches the station 5 minutes before the arrival of train.find the distance covered by him to reach the station?
if a man walks at the rate of 5kmph,he misses a train by only 7 min.however if he walks at the rate of 6kmph he reaches the station 5 minutes before the arrival of train.find the distance covered by him to reach the station?
Let d be the distance travelled to the train in kilometres.
Let s be the speed travelled to reach the train on time in km/h.
Let t be the time taken to reach the train on time, in hours.
d = st
d = 5(t+7/60)
d = 6(t-5/60)
5(t+7/60) = 6(t-5/60)
5t + 35/60 = 6t - 30/60
t = 65/60
d = 5(72/60) = 360/60 = 6 kilometres.
Hello, hena!
Nice job, Sean!
. . I have a slightly difference approach . . .
If a man walks at the rate of 5 km/hr, he misses a train by only 7 minutes.
However, if he walks at the rate of 6 km/hr, he reaches the station 5 minutes early.
Find the distance covered by him to reach the station?
Let = distance to the station.
Let = exact time to reach the station on time.
We will use: .
At 5 km/hr, it takes him: . hours.
. . But he will be 7 minutes late: .
At 6 km/hr, it takes him: . hours.
. . But he will be 5 minutes early: .
Solve the system of equations.
Subtract [2] from [1]: .