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Math Help - Radicals

  1. #1
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    Radicals

    1/3^√2 + 3√3

    do i use the
    a^3+b^3 formula?
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  2. #2
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    Quote Originally Posted by lax600 View Post
    1/3^√2 + 3√3

    do i use the
    a^3+b^3 formula?
    Is this supposed to be
    \frac{1}{\sqrt[3]{2} + \sqrt[3]{3}}

    a^3 + b^3 = (a + b)(a^2 - ab + b^2)

    So
    \frac{1}{\sqrt[3]{2} + \sqrt[3]{3}} \cdot \frac{(\sqrt[3]{2})^2 - \sqrt[3]{2} \sqrt[3]{3} + (\sqrt[3]{3})^2}{(\sqrt[3]{2})^2 - \sqrt[3]{2} \sqrt[3]{3} + (\sqrt[3]{3})^2}

    = \frac{{(\sqrt[3]{2})^2 - \sqrt[3]{2} \sqrt[3]{3} + (\sqrt[3]{3})^2}}{2 + 3} = \frac{\sqrt[3]{4} - \sqrt[3]{6} + \sqrt[3]{9}}{5}

    -Dan
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  3. #3
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    yeah, thx
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