"Two electrons are held, at rest, 1.0x10^-12m apart, then released. With what kinetic energy and speed is each moving when they are a "large" distance apart."

I need help solving for the speed.

I solved for the kinetic energy doing:

/\V = kq/r

/\V = (9.0x10^9 Nm^2/C^2)(1.602x10^-19C)/(1.0x10^-12m)

/\V = 1441.8V

W = /\Ek

/\Ek = q/\V

/\Ek = (1.602X10^-19C)(1441.8V)

/\Ek = 2.3 x 10^16 J

How do I solve for the speed from this point? (answer in the book gives 1.6x10^7m/s)