Here is another attempt to solve the equation:
1. On behalve of the summand x must be greater than zero.
2.
You have to consider 2 different cases:
Then you must solve for x:
The negative solution isn't valid. See #1.
Or
Then you have to solve for x:
The negative solution isn't valid. See #1.
Edit: To my great confusion both solutions don't satisfy the constraints to yield a fraction which is greater than 1.
You're right, I went through the properties again..x cannot possibly be negative. That means these equations have no solution as per you peeps.
That'll be interesting. Wonder what the teacher will say when I point that out .
Anyways thanks for pointing out this huge blunder!
I can write x doesn't belong to R then I guess.