Originally Posted by
SVXX If I take $\displaystyle \log_{4}x$ as y, it will turn out to be a quadratic equation. So I guess we'll have two answers...
$\displaystyle
\log_{x}2 - \log_{4}x = -7/6$
$\displaystyle => \log_{4}2/\_log_{4}x - \log_{4}x = -7/6$
$\displaystyle => 1/2/y - y = -7/6$
$\displaystyle => 1/2y - y = -7/6$
$\displaystyle => 6y*y - 7y - 3 = 0$
The roots for y are 1.5 and 0.3333.
Taking y = 1.5,
$\displaystyle
\log_{4}x = 1.5
$
4 raised to 3/2 or 1.5 is x, or x = 8.
Merci beaucoup, Madame :P