Thread: fenders

choose a number say 156
its factors are 1,2,3,4,6,12,13,26,39,52,156
grouped by last digit (1) (2,12,52) (3,13) (4) (6,26,156) (78) (39)

We say the FENDERS (factor enders) of 156 are 1,2,3,4,6,8,9 &that 156 is a 7-fender (it has seven fenders)
A) Show that a number which has 0 & 9 as fenders has at least four more fenders.
B) Find 3 9-fenders less than 1000 with different sets of fenders?
I know 900 is one(0,1,2,3,4,5,6,8,9) & 420 is another (0,1,2,3,4,5,6,7,8) but can't find another?

This strange and agruably pointless problem has already been answered here .

Also...

(B) 630 (0,1,2,3,5,6,7,8,9)

Originally Posted by Quick

This strange and agruably pointless problem has already been answered here .

Also...

(B) 630 (0,1,2,3,5,6,7,8,9)

630 is a 10 fender (45*14) so still need help

Originally Posted by Quick

This strange and agruably pointless problem has already been answered here .

Also...

(B) 630 (0,1,2,3,5,6,7,8,9)

Help, how 630 is a 8 fender?

KeepSmiling
Malay

Originally Posted by malaygoel

Help, how 630 is a 8 fender?

KeepSmiling
Malay

35*18 gives 630

Originally Posted by bardo

B) Find 3 9-fenders less than 1000 with different sets of fenders?
I know 900 is one(0,1,2,3,4,5,6,8,9) & 420 is another (0,1,2,3,4,5,6,7,8) but can't find another?

It is 270(0,1,2,3,5,6,7,8,9)
KeepSmiling
Malay

Originally Posted by malaygoel

It is 270(0,1,2,3,5,6,7,8,9)
KeepSmiling
Malay

Nope...

There must be some sort of method we are missing, surely a teacher wouldn't make you guess and pick.

Originally Posted by Quick

Nope...

There must be some sort of method we are missing, surely a teacher wouldn't make you guess and pick.

980 is the other 9 fender with 0,1,2,4,5,6,7,8,9

Already discussed here

RonL

Originally Posted by CaptainBlack

Already discussed here

RonL

Question B) wasn't answered in that post