choose a number say 156

its factors are 1,2,3,4,6,12,13,26,39,52,156

grouped by last digit (1) (2,12,52) (3,13) (4) (6,26,156) (78) (39)

We say the FENDERS (factor enders) of 156 are 1,2,3,4,6,8,9 &that 156 is a 7-fender (it has seven fenders)

A) Show that a number which has 0 & 9 as fenders has at least four more fenders.

B) Find 3 9-fenders less than 1000 with different sets of fenders?

I know 900 is one(0,1,2,3,4,5,6,8,9) & 420 is another (0,1,2,3,4,5,6,7,8) but can't find another?