A mass (10 kg) hangs from two strings which are attached to the ceiling shown in this picture:

http://i26.tinypic.com/28h0a6v.jpg

What is the tension in each string?

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- Apr 5th 2008, 05:58 PMcheckmarksforces and tension
A mass (10 kg) hangs from two strings which are attached to the ceiling shown in this picture:

http://i26.tinypic.com/28h0a6v.jpg

What is the tension in each string? - Apr 5th 2008, 06:16 PMmr fantastic
Try using Lami's Theorem: Lami's theorem - Wikipedia, the free encyclopedia

- Apr 5th 2008, 07:21 PMMathstud28The way I am being taught
it in Honors Physics is saying that $\displaystyle \sum{F_x}=0$ and $\displaystyle \sum{F_y}=0$ since this is a statics problem...you set up two equations with two variables based on this and solve them simultaneously...

- Apr 5th 2008, 11:22 PMearboth
The 2 strings must pull together with the same force as the weight of the mass.

Draw the parallelogram of forces. You already know all angles in the marked triangle and the length of the third side. Thus use Sine rule here:

$\displaystyle \frac{|\overrightarrow{F_1}|}{10}=\frac{\sin(40^\c irc)}{\sin(80^\circ)} ~\implies~ |\overrightarrow{F_1}|=10 \cdot \frac{\sin(40^\circ)}{\sin(80^\circ)} \approx 6.527036... kg$ By the way: You are dealing here with forces and therefore the unit**kg**is very, very inappropriate.

$\displaystyle \frac{|\overrightarrow{F_2}|}{10}=\frac{\sin(60^\c irc)}{\sin(80^\circ)} ~\implies~ |\overrightarrow{F_2}|=10 \cdot \frac{\sin(60^\circ)}{\sin(80^\circ)} \approx 8.79385... kg$