for curve y= [(x+1)^0.5]/x area bounded by x-axis, x=3 to x=5 and rotated about x-axis find volume of this solid i got 1.47 units sq but ans. is 2.02 units sq do you need to let u=... eg x=1 or something?
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Originally Posted by dodoje for curve y= [(x+1)^0.5]/x area bounded by x-axis, x=3 to x=5 and rotated about x-axis find volume of this solid i got 1.47 units sq but ans. is 2.02 units sq do you need to let u=... eg x=1 or something? Showing your working would help to find your mistake(s). $\displaystyle V = \pi \int_3^5 \frac{x+1}{x^2} \, dx = \pi \int_3^5 \frac{1}{x} + \frac{1}{x^2} \, dx$. I'd hope this integral was easy for you to do ......
i get what i did wrong used a different method that didn't work out thanks!
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