Quote Originally Posted by Quick
it might be that I'm tired, buy I can't seem to think where you got the 2^(-1/2) from. However, you can see our equations differ,
mine= \frac{d^2}{2^n} yours= 2\left(\frac{1}{2^{(n-1)}}\right)

However, there is a certain value of d that would make our equations the same.

\frac{d^2}{2^n}=2\left(\frac{1}{2^{(n-1)}}\right)
\frac{d^2}{2^n}=\frac{2}{2^{(n-1)}}
\frac{2^2}{2^n}=\frac{2}{2^{(n-1)}}
\frac{4}{2^n}=\frac{2}{2^{(n-1)}}
\frac{2}{2^{(n-1)}}=\frac{2}{2^{(n-1)}}

but why would you say the diameter is 2?
It is given in the question that O1 has radius of 1 unit