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Math Help - manipulating a physics formula

  1. #1
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    manipulating a physics formula

    It's been a while since I've been in school (10yrs). I'm a little rusty at all my math. I wonder if someone could prove how the first formula is the same as the second.
    Cheers!!!
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  2. #2
    Super Member wingless's Avatar
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    Vf^2 = Vi^2 +2a\Delta t

    Subtract Vi^2 from both sides

    Vf^2 - Vi^2 = 2a\Delta t

    Divide both sides by 2\Delta t

    a = \frac{Vf^2 - Vi^2}{2\Delta t}


    I see that this is not the same as the second formula you posted. Yours was a = \frac{Vf^2 - Vi^2}{2\boxed{a}\Delta t}


    I don't even have an idea what formula is this. It looks like the change of position formula of a constant acceleration, without time. Which is,
    \Delta x as the change of position,
    V_1 and V_2 as the first and last velocities,
    a as the constant acceleration

    \Delta x = \frac{V_2^2-V_1^2}{2a}
    Last edited by wingless; March 30th 2008 at 06:21 AM.
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  3. #3
    Forum Admin topsquark's Avatar
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    Obviously, there was a typo in the second equation.

    -Dan
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  4. #4
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    thanks

    Your absolutely right there was a typo in the second equation. I was quite tired when I entered the equation. The equation involves distance rather than " t " time as well. My second lesson here is the importance of proof reading my equations. Thanks again.
    Cheers!!!
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