It's been a while since I've been in school (10yrs). I'm a little rusty at all my math. I wonder if someone could prove how the first formula is the same as the second.

Cheers!!!

Printable View

- March 28th 2008, 07:37 AMvcap420manipulating a physics formula
It's been a while since I've been in school (10yrs). I'm a little rusty at all my math. I wonder if someone could prove how the first formula is the same as the second.

Cheers!!! - March 28th 2008, 10:20 AMwingless

Subtract from both sides

Divide both sides by

I see that this is not the same as the second formula you posted. Yours was

I don't even have an idea what formula is this. It looks like the change of position formula of a constant acceleration, without time. Which is,

as the change of position,

and as the first and last velocities,

as the constant acceleration

- March 28th 2008, 11:34 AMtopsquark
Obviously, there was a typo in the second equation.

-Dan - March 30th 2008, 07:01 AMvcap420thanks
Your absolutely right there was a typo in the second equation. I was quite tired when I entered the equation. The equation involves distance rather than " t " time as well. My second lesson here is the importance of proof reading my equations. Thanks again.

Cheers!!!