# Ionic equation

• Mar 26th 2008, 09:08 AM
chinky
Ionic equation
Balance the ionic equation for acidic conditions. Identify the oxidizing and reducing agents.

$I3^- ---> I^- + IO3^-$

Sorry, not sure how to subscript.
• Mar 26th 2008, 09:11 AM
topsquark
Quote:

Originally Posted by chinky
Balance the ionic equation for acidic conditions. Identify the oxidizing and reducing agents.

$I3^- ---> I^- + IO3^-$

Sorry, not sure how to subscript.

$I_3^- \rightarrow I^- + IO_3^-$
can't be balanced. Where does the O come from?

-Dan
• Mar 26th 2008, 09:51 AM
Stone Cold
Problly the air, if so then...

3I^(3-) + 2O --> 2IO^(3-) + 3I^(-)

However this is my first time doing ionic balancing so its really just a guess.
• Mar 26th 2008, 10:30 AM
topsquark
Quote:

Originally Posted by Stone Cold
Problly the air, if so then...

3I^(3-) + 2O --> 2IO^(3-) + 3I^(-)

However this is my first time doing ionic balancing so its really just a guess.

I doubt it comes from air, though it is possible. In my (admittedly small) experience with these the experiment is done aqueously: in water.

-Dan
• Mar 26th 2008, 11:02 AM
Stone Cold
Quote:

Originally Posted by topsquark
I doubt it comes from air, though it is possible. In my (admittedly small) experience with these the experiment is done aqueously: in water.

-Dan

Well considering Iodine boils at 458 Kelvin you're probably right. (Clapping)