1. simple math problem

I am sorry i don't know how to write the exponents of this problem. The problem is (1 x 10 to the 3rd power kg/in to the 3rd power) times (2 X 10 to the second power in to the 3rd power/gallon).
The answer is supposed to be 2 X 10 to the fifth power kg/gallon.
What happened to inches cubed? Any help would be greatly appreciated and I will gladly pay a membership so I can get some math help. Also any help in accessing math symbols would be a godsend!
Jerry

2. Originally Posted by Jerry Cunningham
I am sorry i don't know how to write the exponents of this problem. The problem is (1 x 10 to the 3rd power kg/in to the 3rd power) times (2 X 10 to the second power in to the 3rd power/gallon).
The answer is supposed to be 2 X 10 to the fifth power kg/gallon.
What happened to inches cubed? Any help would be greatly appreciated and I will gladly pay a membership so I can get some math help. Also any help in accessing math symbols would be a godsend!
Jerry

It cant be, since you have:

$\left[ 1 \times 10^3 {\rm{~kg/in^3}} \right]\times \left[ 2 \times 10^2 {\rm{~per~gallon}} \right]=2 \times 10^5 {\rm{~kg/(gallon.in^3)}}$

Now we could comvert the cubic inches into gallons then the dimensions
would become $\rm{kg/gallon^2}$ but the numeric value would no longer be that given.

(for mathematical notation in the forum see here)

RonL