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Math Help - simple math problem

  1. #1
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    simple math problem

    I am sorry i don't know how to write the exponents of this problem. The problem is (1 x 10 to the 3rd power kg/in to the 3rd power) times (2 X 10 to the second power in to the 3rd power/gallon).
    The answer is supposed to be 2 X 10 to the fifth power kg/gallon.
    What happened to inches cubed? Any help would be greatly appreciated and I will gladly pay a membership so I can get some math help. Also any help in accessing math symbols would be a godsend!
    Jerry
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by Jerry Cunningham View Post
    I am sorry i don't know how to write the exponents of this problem. The problem is (1 x 10 to the 3rd power kg/in to the 3rd power) times (2 X 10 to the second power in to the 3rd power/gallon).
    The answer is supposed to be 2 X 10 to the fifth power kg/gallon.
    What happened to inches cubed? Any help would be greatly appreciated and I will gladly pay a membership so I can get some math help. Also any help in accessing math symbols would be a godsend!
    Jerry

    It cant be, since you have:

    \left[ 1 \times 10^3 {\rm{~kg/in^3}} \right]\times \left[ 2 \times 10^2 {\rm{~per~gallon}} \right]=2 \times 10^5  {\rm{~kg/(gallon.in^3)}}

    Now we could comvert the cubic inches into gallons then the dimensions
    would become \rm{kg/gallon^2} but the numeric value would no longer be that given.

    (for mathematical notation in the forum see here)

    RonL
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