Thread: simple math problem

I am sorry i don't know how to write the exponents of this problem. The problem is (1 x 10 to the 3rd power kg/in to the 3rd power) times (2 X 10 to the second power in to the 3rd power/gallon).
The answer is supposed to be 2 X 10 to the fifth power kg/gallon.
What happened to inches cubed? Any help would be greatly appreciated and I will gladly pay a membership so I can get some math help. Also any help in accessing math symbols would be a godsend!
Jerry

Originally Posted by Jerry Cunningham

I am sorry i don't know how to write the exponents of this problem. The problem is (1 x 10 to the 3rd power kg/in to the 3rd power) times (2 X 10 to the second power in to the 3rd power/gallon).
The answer is supposed to be 2 X 10 to the fifth power kg/gallon.
What happened to inches cubed? Any help would be greatly appreciated and I will gladly pay a membership so I can get some math help. Also any help in accessing math symbols would be a godsend!
Jerry

It cant be, since you have:



Now we could comvert the cubic inches into gallons then the dimensions
would become but the numeric value would no longer be that given.

(for mathematical notation in the forum see here)

RonL