# Physics - Power

• Mar 5th 2008, 12:23 PM
vesperka
Physics - Power
In one second, $1.4\times10^6\ \textrm{kg}$ of water passes through that particular section. The work done by gravity on this mass of water as it falls through $59\ \textrm{m}$ is $1.4\times10^6\times9.8\times59=8.0948\times10^8\ \textrm{J}$. This is the amount of energy “wasted” per second; hence the power wasted by the waterfall is $8.0948\times10^8\ \textrm{W}$.