# Word Problems - Distance between 2 objects, maximizing area, and more

• February 27th 2008, 06:54 AM
xkncx
Word Problems - Distance between 2 objects, maximizing area, and more
I just need help on questions 7, 8, 9, 12, and 13

For question 7, I keep thinking that the pool area is a square, so wouldn't all sides be equally fenced? Therefore wouldn't the 25M be equally divided by 4 to maximize area?

http://i238.photobucket.com/albums/f...hmwrk_0001.jpg
http://i238.photobucket.com/albums/f...hmwrk_0002.jpg

• February 27th 2008, 07:15 AM
Peritus
7. square is just a special case of rectangle whose adjacent sides are equal.

let's denote one of the sides as a and the other as b thus:

$\begin{gathered}
2\left( {a + b} \right) = 25 \hfill \\
S = ab = a\left( {\frac{{25}}
{2} - a} \right) \hfill \\
\end{gathered}$

now let's differentiate S(a):

$\frac{{dS}}
{{da}} = \frac{{25}}
{2} - 2a = 0 \Rightarrow a = \frac{{25}}
{4},b = \frac{{25}}
{4}$

you can differentiate S one more time to make sure that it's maxima.
• February 27th 2008, 07:25 AM
colby2152
8) Max revenue is when R'(x)=0

$R'(x)=-10x+21$

$x=2.1$

Profit at that point is $R(21)-C(21) = -5(2.1)^2+21(2.1)-4(2.1)-14 \Rightarrow ???$

(Yes)