# Looking for help with word problem

• May 9th 2006, 05:17 PM
sugar_babee
Looking for help with word problem
Jaime bought a case of concert T-shirts for $450. She kept 2 for herself and sold the rest for$560, making a profit of $10 on each shirt. How many shirts were in the case? I cant figure out the equations to make this work, if someone could help that would be great • May 9th 2006, 05:32 PM ticbol Quote: Originally Posted by sugar_babee Jaime bought a case of concert T-shirts for$450. She kept 2 for herself and sold the rest for $560, making a profit of$10 on each shirt. How many shirts were in the case?
I cant figure out the equations to make this work, if someone could help that would be great

I just passed by and took a peek. Solved this on paper eal quick.
There were 18 shirts in the case.
She sold 16 for $35 each. Gotta go. I'd show the computations after work, or about 6 hours from now. Sorry. • May 9th 2006, 08:26 PM earboth Quote: Originally Posted by sugar_babee Jaime bought a case of concert T-shirts for$450. She kept 2 for herself and sold the rest for $560, making a profit of$10 on each shirt. How many shirts were in the case?

I cant figure out the equations to make this work, if someone could help that would be great

Hello,

1. contents of case: x
2. contents of case after self supply: x-2
3. price to be paid: y
4. price when sold: y+10

You get 2 equations:

$x \cdot y=450$
$(x-2)(y+10)=560$

Because you want to know x, solve equation 1 for y and plug this term into equation 2:

$(x-2)(\frac{450}{x}+10)=560$

After a few transformations you'll get:

$10x^2-130x-900=0$

Solve for x and you get x=18 or x=-5. The negative result isn't very realistic.

Greetings

EB
• May 10th 2006, 03:48 AM
sugar_babee
Thanks a lot :) I was just way overthinking the problem...i have trouble with word problems