# Multiple choice

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• Feb 23rd 2008, 07:58 PM
run_run_3
Multiple choice
Hi

can anyone help me with the problem below?

The total cost for five items of repair work on a car was 195. Overhaul of the carburetor cost twice as much as the tune-up, brake pads cost one-third as much as the carburetor overhaul, and alignment and wheel balancing each cost one-third as much as the tune-up. What did the tune-up cost? A.30
B. $45 C.$60
D. $90 E. One cannot tell from the information given. • Feb 23rd 2008, 08:11 PM Jhevon Quote: Originally Posted by run_run_3 Hi can anyone help me with the problem below? The total cost for five items of repair work on a car was$195. Overhaul of the carburetor cost twice as much as the tune-up, brake pads cost one-third as much as the carburetor overhaul, and alignment and wheel balancing each cost one-third as much as the tune-up. What did the tune-up cost?

A. $30 B.$45
C. $60 D.$90
E. One cannot tell from the information given.

let $x$ be the cost of the tuneup.

then the cost of the carburetor overhaul is $2x$

the cost of the brake pads is $\frac 13 (2x)$

the costs of alignment and wheel balancing are $\frac 13x$ each.

sum all these, equate to 195 and solve for x
• Feb 23rd 2008, 08:25 PM
calcprincess88
can anyone help me with the problem below?

The total cost for five items of repair work on a car was 195. Overhaul of the carburetor cost twice as much as the tune-up, brake pads cost one-third as much as the carburetor overhaul, and alignment and wheel balancing each cost one-third as much as the tune-up. What did the tune-up cost? A.30
B. $45 C.$60
D. 90 E. One cannot tell from the information given. Here's what you do: When you are given a problem like this you need to read the whole question and see how much information you are given. What is given in this problem is: Total Cost = 195 Overhaul of the carburetor = 2*tune-up brake pads = (1/3)*Overhaul of the carburetor=(1/3)*2*tune-up alignment = (1/3)*tune-up wheel balancing = (1/3)*tune-up Now you can take this information and add them together because they all have the same variable in them (i.e. tune-up) and set them equal to 195. So you get: 2*tune-up+(1/3)*2*tune-up+(1/3)*tune-up+(1/3)*tune-up=195 The answer you get is how much your tune-up cost. Hope this helps! (Nod) • Feb 23rd 2008, 09:37 PM Jhevon Quote: Originally Posted by calcprincess88 can anyone help me with the problem below? The total cost for five items of repair work on a car was195. Overhaul of the carburetor cost twice as much as the tune-up, brake pads cost one-third as much as the carburetor overhaul, and alignment and wheel balancing each cost one-third as much as the tune-up. What did the tune-up cost?

A. $30 B.$45
C. $60 D.$90
E. One cannot tell from the information given.

Here's what you do:

When you are given a problem like this you need to read the whole question and see how much information you are given. What is given in this problem is:

Total Cost = 195
Overhaul of the carburetor = 2*tune-up
brake pads = (1/3)*Overhaul of the carburetor=(1/3)*2*tune-up
alignment = (1/3)*tune-up
wheel balancing = (1/3)*tune-up

Now you can take this information and add them together because they all have the same variable in them (i.e. tune-up) and set them equal to 195. So you get:

2*tune-up+(1/3)*2*tune-up+(1/3)*tune-up+(1/3)*tune-up=195

The answer you get is how much your tune-up cost.

Hope this helps! (Nod)

Ah, another female mathematician! welcome aboard!

you are female aren't you? otherwise calling yourself "princess" is, well, weird