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Hi
can anyone help me with the problem below?
The total cost for five items of repair work on a car was $195. Overhaul of the carburetor cost twice as much as the tune-up, brake pads cost one-third as much as the carburetor overhaul, and alignment and wheel balancing each cost one-third as much as the tune-up. What did the tune-up cost?
A. $30
B. $45
C. $60
D. $90
E. One cannot tell from the information given.
letQuote:
Originally Posted by run_run_3
be the cost of the tuneup.
then the cost of the carburetor overhaul is
the cost of the brake pads is
the costs of alignment and wheel balancing areeach.
sum all these, equate to 195 and solve for x
can anyone help me with the problem below?
The total cost for five items of repair work on a car was $195. Overhaul of the carburetor cost twice as much as the tune-up, brake pads cost one-third as much as the carburetor overhaul, and alignment and wheel balancing each cost one-third as much as the tune-up. What did the tune-up cost?
A. $30
B. $45
C. $60
D. $90
E. One cannot tell from the information given.
Here's what you do:
When you are given a problem like this you need to read the whole question and see how much information you are given. What is given in this problem is:
Total Cost = 195
Overhaul of the carburetor = 2*tune-up
brake pads = (1/3)*Overhaul of the carburetor=(1/3)*2*tune-up
alignment = (1/3)*tune-up
wheel balancing = (1/3)*tune-up
Now you can take this information and add them together because they all have the same variable in them (i.e. tune-up) and set them equal to 195. So you get:
2*tune-up+(1/3)*2*tune-up+(1/3)*tune-up+(1/3)*tune-up=195
The answer you get is how much your tune-up cost.
Hope this helps! (Nod)
Ah, another female mathematician! welcome aboard!Quote:
Originally Posted by calcprincess88
you are female aren't you? otherwise calling yourself "princess" is, well, weird