The answer is supposed to be 6/piA ball with radius r fits snugly in a cubical box. Determine the ratio of the surface area of the box to the surface area of the ball.
The surface area of a box is 6s^2 and the surface area of a sphere is 4pi(r^2)
I think that would be
6(r^2) over 4pi(r^2)
the two (r^2) cancel out so I'm left with 6/4pi
I don't know what to do from there.