Just checking my work ...

$\displaystyle distance=s=200t-16t^2$ velocity at 2sec = $\displaystyle v=(2)$?

I did

$\displaystyle s=-32T+200$

to

$\displaystyle s=200-64=136$

Is that correct? The Vs and Ts messed me all up. I wanted to make sure there wasn't a second derivative involved