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Thread: Distance and velocity

  1. #1
    Member
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    Distance and velocity

    Just checking my work ...

    $\displaystyle distance=s=200t-16t^2$ velocity at 2sec = $\displaystyle v=(2)$?

    I did

    $\displaystyle s=-32T+200$

    to

    $\displaystyle s=200-64=136$

    Is that correct? The Vs and Ts messed me all up. I wanted to make sure there wasn't a second derivative involved
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  2. #2
    Super Member wingless's Avatar
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    It seems correct

    S : distance
    V : Velocity
    a : acceleration,

    $\displaystyle a = \frac{dV}{dt}$

    $\displaystyle V = \frac{dS}{dt}$
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