and I'm wondering what the easiest way to solve out a is, cause i've been trying and it just ends up looking worse than it did before i started out.. ^^
and I'm wondering what the easiest way to solve out a is, cause i've been trying and it just ends up looking worse than it did before i started out.. ^^
What are you trying to find? if a=0 or a=1 the system is degenerate (reduces
to two independent equations) and so has multiple solutions, any other
value of a will allow a unique solution for x, y and z in terms of a.
What are you trying to find? if a=0 or a=1 the system is degenerate (reduces
to two independent equations) and so has multiple solutions, any other
value of a will allow a unique solution for x, y and z in terms of a.
RonL
I think the system will have no solution for a = 0 ......
2x - y + 3z = 4 ..... (1)
x + y = 3 .... (2)
x + z = 3 ..... (3)
(1) + (2): 3x + 3z = 7 => x + z = 7/3 is inconsistent with (3).