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Math Help - emf and current of square coil.

  1. #1
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    emf and current of square coil.

    A magnetic field is perpendicular to the plane of a single-turn circular coil. The magnitude of the field is changing, so that an emf of 0.91 V and a current of 3.2 A are induced in the coil. The wire is the re-formed into a single-turn square coil, which is used in the same magnetic field (again perpendicular to the plane of the coil and with a magnitude changing at the same rate). What emf and current are induced in the square coil?

    emf V:

    and

    current A:

    please explain this one.
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  2. #2
    Senior Member
    Joined
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    L = 2*pi*r,
    A = L/4*pi,
    A = L^2/16

    Okay i know the lengths are the same for the circular coil and the square coil. Oh and the form has changed.

    So A1/A2 = (L^2/4*pi) / (L^2/16) = 16/4*pi

    and for the current i could use I2 = V2/R

    and i'm not sure but i think R = V1/I1 ?

    I've put some formulas together with some help, can someone work the rest of this out, i have just about all the formulas i believe.
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