A mass of 0.3 kg is suspended from a spring of stiffness 200 N m–1. Ifthe mass is displaced by 10 mm from its equilibrium position andreleased, for the resulting vibration:

Plot a graph of acceleration against displacement (x) (for values ofxfromx= –10 mm tox= +10 mm)

Hugely struggling to plot and draw this graph. Have been reading about a formula to give values for the acceleration but this formula is giving me numbers which seem way off.

Formula: -(w^2 times displacement)

So, -25.81^2 x 0.1= -66.61561???

Am I on the right track or miles off?? First post and any help is greatly appreciated!