I am having trouble factoring this problem:
8x^3y^6 + 27
I also want to know if I have factored correctly on this problem:
a^3b^6 - b^3
My answer to this question (ab^3-b)^3
Am I right?
$\displaystyle 8x^3 y^6 + 27$
$\displaystyle (2x y^2)^3 + 3^3$
This is a Sum of two cubes and you should know.
$\displaystyle a^3 + b^3 = (a+b)(a^2-ab+b^2)$
and i guess your expected to use $\displaystyle a^3 - b^3 = (a-b)(a^2+ab+b^2)$
for the second question.