Ok here is the question:

For a charity event, some students assembled one million small plastic cubes to form a massive cube. How many small cube faces could be seen on one face of the finished massive cubes?

I thought it would be cube root of 1 000 000 = 100 squared.

Thats not the answer thats in the book.

2. Originally Posted by kimki
Ok here is the question:

For a charity event, some students assembled one million small plastic cubes to form a massive cube. How many small cube faces could be seen on one face of the finished massive cubes?

I thought it would be cube root of 1 000 000 = 100 squared.

Thats not the answer thats in the book.

If the book does not say 10000, what does it say?

RonL

3. it says 60 000

4. If you have 1,000,000 cubes and you use them to form a monster cube, then you need that,
$(\mbox{side})^3=1,000,000$
That happens when the side got 100 cubes.
Each face of a cube is 100x100 cubes thus they are
10,000 cubes visible on one side. But there are 6 side to a cube thus, 60,000 cubes visible.

5. Originally Posted by ThePerfectHacker
If you have 1,000,000 cubes and you use them to form a monster cube, then you need that,
$(\mbox{side})^3=1,000,000$
That happens when the side got 100 cubes.
Each face of a cube is 100x100 cubes thus they are
10,000 cubes visible on one side. But there are 6 side to a cube thus, 60,000 cubes visible.
So that implies that the wording of the question that we have been given

RonL

6. Originally Posted by ThePerfectHacker
If you have 1,000,000 cubes and you use them to form a monster cube, then you need that,
$(\mbox{side})^3=1,000,000$
That happens when the side got 100 cubes.
Each face of a cube is 100x100 cubes thus they are
10,000 cubes visible on one side. But there are 6 side to a cube thus, 60,000 cubes visible.
Actually, if the problem works like that there are only 50,000 because the bottom face is not visible.

-Dan

7. Originally Posted by ThePerfectHacker
If you have 1,000,000 cubes and you use them to form a monster cube, then you need that,
$(\mbox{side})^3=1,000,000$
That happens when the side got 100 cubes.
Each face of a cube is 100x100 cubes thus they are
10,000 cubes visible on one side. But there are 6 side to a cube thus, 60,000 cubes visible.
Should we take account of triple counting the 8 corner cubes or double
counting the 12*98 edge cubes?

RonL

8. Also, in the question it states how many cubes are visable in ONE FACE. Doesnt that mean one side of the cube? ie 10,000?! 1002

9. Originally Posted by topsquark
Actually, if the problem works like that there are only 50,000 because the bottom face is not visible.

-Dan
That type of fact only matters in physics type problems.

10. Originally Posted by ThePerfectHacker
That type of fact only matters in physics type problems.
Translation: REAL problems.

-Dan