current in Amps and Ions
Suppose that the resistance between the walls of a biological cell is 1.90 x 10^10 .
(a) What is the current when the potential difference between the walls is 90 mV?
(b) If the current is composed of Na+ ions (q = +e), how many such ions flow in 1.5 s?
i know that Ohm's Law (V=IR) probably applies to this problem, along with Electromotive Force
Originally Posted by rcmango
V = 90 mV
R = 1.90 x 10^10
I = V/R = (90 mV) / (1.90 x 10^10)
Where does that leave us? There is a bit of arithmetic to go.