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Math Help - anyone know the answers to these?

  1. #1
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    Angry anyone know the answers to these?

    1. A test was carried out on a electrical circuit and the following resaults obtained:

    4t1+t2=6
    -3t1+5t2=0

    the 1s and 2s are lower case dont know how to do it sorry!

    solve analytically the above simultaneous equatios and check your answer by plotting their graphs on the same set of axes

    2. the area of a rectangle is 25.2m2 (squared) and the width is 3.2 metres shorter than the length. calculate the dimentions of the rectangle.

    3. solve by factorising the following equations:
    x(squared)-6x+9=0
    6x(squared)+x-15=0

    if anyone can work these out or help me i would be much app cheers!
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  2. #2
    Bar0n janvdl's Avatar
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    Quote Originally Posted by jenko View Post
    1. A test was carried out on a electrical circuit and the following resaults obtained:

    4t1+t2=6
    -3t1+5t2=0
    by plotting their graphs on the same set of axes
    Let t_{1} = x and t_{2} = y and then draw a graph using it as the y = mx + c formula

    Quote Originally Posted by jenko View Post

    2. the area of a rectangle is 25.2m2 (squared) and the width is 3.2 metres shorter than the length. calculate the dimentions of the rectangle.
    L \times W = A

    A = 25,2 m^2

    L = x \ metres

    W = (x - 3,2) \ metres

    So we know that (x)(x - 3,2) = 25,2

    Quote Originally Posted by jenko View Post

    3. solve by factorising the following equations:
    x(squared)-6x+9=0
    6x(squared)+x-15=0
     x^2 - 6x + 9 = 0

     (x - 3)(x - 3) = 0

     (x - 3)^2 = 0

    ---

     6x^2 + x - 15 = 0

     (3x + 5)(2x - 3) = 0


    You can solve them.
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  3. #3
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    are these the answers or formulas?
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  4. #4
    Bar0n janvdl's Avatar
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    Quote Originally Posted by jenko View Post
    are these the answers or formulas?
    These are basically answers. You just have to finish them off.
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  5. #5
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    what are the final answers ive worked them out i need to check them now
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  6. #6
    Bar0n janvdl's Avatar
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    Quote Originally Posted by jenko View Post
    what are the final answers ive worked them out i need to check them now
    What are your answers?
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  7. #7
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    i found the length and width of the square but i did not to do it the way of the question but heres what i got

    Area=LxW
    4.675x5.390= 25.19 is this the correct answer ? but how do i work it out as the question asked?
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  8. #8
    Bar0n janvdl's Avatar
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    Quote Originally Posted by jenko View Post
    i found the length and width of the square but i did not to do it the way of the question but heres what i got

    Area=LxW
    4.675x5.390= 25.19 is this the correct answer ? but how do i work it out as the question asked?
    You have to expand L x W and you have to take the Area over to the left side, to get the right side equal to 0. Then solve.
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  9. #9
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    sorry completely confused can you give me an example using different numbers? tha i can work off? for the questions above? cheers
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  10. #10
    Bar0n janvdl's Avatar
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    Quote Originally Posted by janvdl View Post
    L \times W = A

    A = 25,2 m^2

    L = x \ metres

    W = (x - 3,2) \ metres

    So we know that (x)(x - 3,2) = 25,2
    I am quite certain you know how to use the quadratic formula.

    x^2 - 3,2x = 25,2

    x^2 - 3,2x - 25,2 = 0

    Now use the quadratic formula to solve for x. It's that simple.
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  11. #11
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    no i dont this has just completly confused me ! i realy havent a clue for these ive looked at my notes and i couldnt find anything :S i need each question broken dwn induvadually so do these i cannot find any notes on these in my books from previous lessons these re only practice questions ready for my summer exam it jus the fact that im trying to get these into my head with out using notes as my exams are not open book (allowed to look at notes whilst in exam)
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  12. #12
    Bar0n janvdl's Avatar
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    Quote Originally Posted by jenko View Post
    no i dont this has just completly confused me ! i realy havent a clue for these ive looked at my notes and i couldnt find anything :S i need each question broken dwn induvadually so do these i cannot find any notes on these in my books from previous lessons these re only practice questions ready for my summer exam it jus the fact that im trying to get these into my head with out using notes as my exams are not open book (allowed to look at notes whilst in exam)
    Well then it wont help to just give you the answers.

    The quadratic formula is the following:

    x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

    Where a, b and c are co-efficients of:

    ax^2 + bx + c = 0
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  13. #13
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    where shalll we start?
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