Hey I'm not sure how you solve this. Calculate to the nearest degree the values of x when sin x = 0.2, for -180degrees < x < 180degrees.
It depends on what you mean by calculate. I would normaly use the inverseOriginally Posted by digideens
sin function on a calculator to do this. It can be done using Newton Raphson
or a number of other techniques.
There is also the problem that there are two solutions in the specified range.
You need to use a function on your calculator called the arc-sin or sometimes written as it tell you the inverse operation.Originally Posted by digideens
You find, (have calculator in degree mode).
But that is still not it. Because the sine is also positive in the second Quadrant. In the second quadrant the value is,