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Math Help - Sin Graph Help

  1. #1
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    Sin Graph Help

    Hey I'm not sure how you solve this. Calculate to the nearest degree the values of x when sin x = 0.2, for -180degrees < x < 180degrees.
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by digideens
    Hey I'm not sure how you solve this. Calculate to the nearest degree the values of x when sin x = 0.2, for -180degrees < x < 180degrees.
    It depends on what you mean by calculate. I would normaly use the inverse
    sin function on a calculator to do this. It can be done using Newton Raphson
    or a number of other techniques.

    There is also the problem that there are two solutions in the specified range.

    RonL
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  3. #3
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    Quote Originally Posted by digideens
    Hey I'm not sure how you solve this. Calculate to the nearest degree the values of x when sin x = 0.2, for -180degrees < x < 180degrees.
    You need to use a function on your calculator called the arc-sin or sometimes written as \sin^{-1} it tell you the inverse operation.
    Thus, for
    \sin x=.2
    You find, (have calculator in degree mode).
    x=\sin^{-1}(.2)\approx 11.54^o
    But that is still not it. Because the sine is also positive in the second Quadrant. In the second quadrant the value is,
    180^o-11.54^o\approx 168.46^o
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  4. #4
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    Thanks for the quick replies guys, I got it now.
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