Hey I'm not sure how you solve this. Calculate to the nearest degree the values of x when sin x = 0.2, for -180degrees < x < 180degrees.

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- April 23rd 2006, 02:34 PMdigideensSin Graph Help
Hey I'm not sure how you solve this. Calculate to the nearest degree the values of x when sin x = 0.2, for -180degrees < x < 180degrees.

- April 23rd 2006, 02:47 PMCaptainBlackQuote:

Originally Posted by**digideens**

sin function on a calculator to do this. It can be done using Newton Raphson

or a number of other techniques.

There is also the problem that there are two solutions in the specified range.

RonL - April 23rd 2006, 02:48 PMThePerfectHackerQuote:

Originally Posted by**digideens**

Thus, for

You find, (have calculator in degree mode).

But that is still not it. Because the sine is also positive in the second Quadrant. In the second quadrant the value is,

- April 23rd 2006, 02:51 PMdigideens
Thanks for the quick replies guys, I got it now.