The inner and outer surfaces of a cell membrane carry a negative and positive charge, respectively. Because of these charges, a potential difference of about 0.060 V exists across the membrane.
The thickness of the membrane is 9.00 x 10^-9 m. What is the magnitude of the electric field in the membrane?
i believe the equation to be: E = V/r
not sure why .060V / 9.00 x 10^-9 would not work???
thanks for any help.