1. quick physics question

A cannonball shot horizontally from the top of a cliff with an initial velocity of 425m/s is aimed towards a schooner on the ocean below. If the cliff is 78m above the ocean surface, calculate the following:
a) the time for the cannonball to reach the water
b) horizontal displacement of the cannonball
c) final velocity

Can someone please help me with part c).... the final answer is suppose to be $\displaystyle 4.3 x 10^2m/s$[E 5.3deg N]

thanks

2. Originally Posted by johett
A cannonball shot horizontally from the top of a cliff with an initial velocity of 425m/s is aimed towards a schooner on the ocean below. If the cliff is 78m above the ocean surface, calculate the following:
a) the time for the cannonball to reach the water
b) horizontal displacement of the cannonball
c) final velocity

Can someone please help me with part c).... the final answer is suppose to be $\displaystyle 4.3 x 10^2m/s$[E 5.3deg N]

thanks
Read similar posted question again - I edited part d) to include a tip on getting direction. Reply here if you still can't do c). And reply over there if you still can't do any of a) - d).

Also, giving the direction of the final velocity using (almost) conventional bearings means that you need to say which direction the initial velocity (N, S E or W?) is in, that is, what is the direction of horizontal from top of cliff (N, S, E or W?)