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  1. #1
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    Physics2

    A bomber in level flight, flying at 92m/s, releases a bomb at a height of
    1950m.

    a)how long is it before the bomb strikes the earth?
    b)how far does it travel horizontally?
    c)what are the horizontal and vertical components of its velocity when it strikes?
    d)what is its velocity of impact?

    -thanks!
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  2. #2
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    Quote Originally Posted by johett View Post
    A bomber in level flight, flying at 92m/s, releases a bomb at a height of
    1950m.

    a)how long is it before the bomb strikes the earth?
    b)how far does it travel horizontally?
    c)what are the horizontal and vertical components of its velocity when it strikes?
    d)what is its velocity of impact?

    -thanks!
    You're probably told to ignore air resistance. Then all questions use the straight-line motion formulae under constant acceleration, applied as required in the horizontal and vertical components of the motion of the bomb.

    a) Vertical component: Take downwards as positive. u = 0 m/s, y = 1950 m, a = g = either 9.8 or 10 m/s^2 (use the value you've been told to use), t = ?

    b) Horizontal component: u = 92 m/s, a = 0 m/s^2, t = get from (a), x = ?

    c) Vertical component: Take downwards as positive. u = 0 m/s, y = 1950 m, a = g = either 9.8 or 10 m/s^2 (use the value you've been told to use), v_y = ?

    Horizontal component: u = 92 m/s, a = 0 m/s^2, t = get from (a), v_x = ?

    d) Speed: v^2 = v_x^2 + v_y^2.
    Direction: At an angle \theta = \tan^{-1}\left( \frac{v_y}{v_x} \right) to the horizontal. Do you see why?

    Question of related interest (either now or very soon): Question 2 of this thread.
    Last edited by mr fantastic; January 14th 2008 at 04:18 PM. Reason: Edited part d): Gave formula for getting direction of final velocity
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