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**ForgottenMemorie** The distance traveled by a car in a time t seconds afer the brakes are applied is given by:

$\displaystyle y= 10t-1.8t^2$

Where y is the distance in metres and t is time in seconds.

Determine equations for velocity and acceleration of the car.

What is the velocity at the instant the brakes are applied?

How many seconds does it take the car to stop?

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$\displaystyle 10t$

$\displaystyle 1.8t^2 = 3.24t$

$\displaystyle 10t - 3.24t = 6.76$

$\displaystyle Time = 6.76 Seconds? $

Whats the next step? and is that correct so far? help welcomed please.

I know that $\displaystyle V= dx/dt $