For , divide both sides by .
.
We found , which makes the equation true, but don't forget that we didn't test for . If we do,
Yes, is a root too.
Hi, I have this part of a question that gets me:
I did all the previous steps and got to an equation that must =0:
x^2(-x+12)=0
I know that making x=12 is one value, but for the x^2 part, do i just ignore it?
In my answer book it says x=12 and nothing else, so I'm presuming its something to do with real values of x (even though I don't really know what a 'real' value of x is).
Thanks